KRamsauer
TreoCentral Staff

Registered: Apr 2002
Location: Houston, TX
Posts: 734 |
quote: Originally posted by Toby
The only time that the odds are 2 out of 3 is if the host is required to offer the switch _all_the_time_ (which was not the case on LMAD) and has foreknowledge of the location of the prize. Again, you're letting raw statistics fool you into a conclusion not supported by reality. I don't need a stat prof. I used to watch the show. Again, the flaw is trying to impose statistics on reality. It just doesn't work that way.
Hm... The more I've thought about it, I've realized you can relax the "always offer the switch" assumption. So long as the host doesn't know where the prize is, it is still best to always switch when given the chance. In other words, if the choice of doors to reveal and the choice to reveal that door are made by seperate entities, it's still best to always switch. Only when the choice to allow a switch and then the choice of door to reveal covary does the strategy of switching not necessarily beat other strategies.
So even if Monty made the choice to allow a switch, so long as he didn't know what door contained the answer (he'd ask for an empty door to be revealed, not ask for a given door to be revealed), it still pays to switch every time given the chance. So in this light, my original formulation still holds if I don't know what door has the prize.
Conversely, if I know where the prize is, and I don't have a choice of whether or not to offer you a switch, again it always pays to switch. The solution is more powerful than I lead on, I guess.
Last edited by KRamsauer on 10-17-2002 at 09:58 PM
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